Which of the following points are NOT on the graph of y = x^2 - 1?
A. (0, -1)
B. (1, 0)
C. (-1, 0)
D. (0, 0)
well, did you actually try the values to see which are or are not?
(0,-1): -1 = 0^2-1? yes
now you try the others and we can check your answers.
it is D
Yes
To determine which points are not on the graph of the equation y = x^2 - 1, we can substitute the x and y values of each point into the equation and see if it is a true statement.
Let's go through each option:
A. (0, -1):
Substituting x = 0 and y = -1 into the equation:
-1 = 0^2 - 1
-1 = -1
Since this equation is true, point A (0, -1) is on the graph.
B. (1, 0):
Substituting x = 1 and y = 0 into the equation:
0 = 1^2 - 1
0 = 0
Since this equation is true, point B (1, 0) is on the graph.
C. (-1, 0):
Substituting x = -1 and y = 0 into the equation:
0 = (-1)^2 -1
0 = 0
Since this equation is true, point C (-1, 0) is on the graph.
D. (0, 0):
Substituting x = 0 and y = 0 into the equation:
0 = 0^2 - 1
0 = -1
Since this equation is false, point D (0, 0) is NOT on the graph.
Therefore, the answer is D. (0, 0) is not on the graph of y = x^2 - 1.