The Mathletes won 2 of their first 10 meets. They went on to win all their remaining meets and finished the year with an equal number of wins and losses. What is the total number of meets in which the Mathletes competed?
16
To find the total number of meets in which the Mathletes competed, we first need to determine the number of meets they won after the first 10 meets.
Given that the Mathletes won 2 of their first 10 meets, we can calculate the number of remaining meets they won. Since they finished the year with an equal number of wins and losses, they must have won an additional 8 meets after the first 10 meets. This is because for them to have an equal number of wins and losses, they would need to win the same number of meets as they lost.
Therefore, the Mathletes won a total of 2 + 8 = 10 meets.
To find the total number of meets in which the Mathletes competed, we add the number of meets they won to the number of meets they lost. Since they won 10 meets, we know they must have also lost 10 meets.
Thus, the total number of meets in which the Mathletes competed is 10 + 10 = 20 meets.
If there were x more meets to go, and they won them all, then, since the wins = the losses
2+x = 10-2
take it from there. Note that the value of x is not the answer.