What amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4.18 J/g°C.
1200 joules
1500 joules
1700 joules
1900 joules
2000 joules
20 g ( 4.18 J/g deg C )(30 deg C-10 deg C)
= 1672 J
which is closer to 1700 than to anything else on your list.
To calculate the heat required to raise the temperature of a substance, you can use the formula:
Heat = mass × specific heat capacity × change in temperature
Given:
Mass of water = 20 grams
Specific heat capacity of water = 4.18 J/g°C
Change in temperature = 30°C - 10°C = 20°C
Using the formula, we can calculate the heat required:
Heat = 20 grams × 4.18 J/g°C × 20°C
Heat = 1664 joules
Therefore, the amount of heat required to raise the temperature of 20 grams of water from 10°C to 30°C is approximately 1664 joules.
None of the provided options exactly match the calculated value.
To calculate the amount of heat required to raise the temperature of a substance, you can use the formula:
q = m * c * ΔT
Where:
q is the amount of heat (in joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
In this case, we need to raise the temperature of 20 grams of water from 10°C to 30°C, so:
m = 20 grams
c = 4.18 J/g°C
ΔT = (30°C - 10°C) = 20°C
Plugging the values into the formula, we have:
q = 20 grams * 4.18 J/g°C * 20°C
q = 1672 joules
Therefore, the amount of heat required to raise the temperature of 20 grams of water from 10°C to 30°C is approximately 1672 joules.
Out of the given options, the closest value is 1700 joules.