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mg +2Hcl --MgCl2. + h2
Calculate minimum volume of 0.1ml\L
Please help
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mg +2Hcl --MgCl2. + h2
Calculate minimum volume of 0.1ml\L Please help
Top answer:
To calculate the minimum volume of a 0.1M HCl solution required to react completely with a certain
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Calculate the volume of gas you would expect to be evolved in X mol of magnesium were reacted with an excess of HCl at standard
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I think this would classify as a single replacement rxn.
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consider the following reaction: Mg(s)+ 2HCl(aq) --> MgCl2 (aq)+H2 (g)
What minimum amount of 1.75 M HCl is necessary to produce
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See above.
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consider the following reaction: Mg(s)+ 2HCl(aq) --> MgCl2 (aq)+H2 (g)
What minimum amount of 1.75 M HCl is necessary to produce
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Convert 27.5 L H2 at STP to moles. L/22.4 = moles. Using the coefficients in the balanced equation,
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What is the minimum amount of 1.75 m of HCL necessary to produce 28.5 L of H2 at stp?
EQUATION IS AS FOLLOWS: Mg+2HCL->>MgCl2+H2
Top answer:
Is that an m or an M? I will assume you made a typo or didn't know any better and you meant M. Also,
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I'm trying to calculate the enthalpy of the reaction
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2 (g) however I cannot find the enthalpy of
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My text gives -641.8 kJ/mol MgCl2(s)as delta Hformation.
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When 1.38 g of magnesium is added to 25 mL of 2.0 M hydrochloric acid, hydrogen
gas is released according to the equation below:
Top answer:
1.38g Mg = 0.051 moles 25mL * 2.0 M = 0.05 moles HCl So it looks like only 0.025 moles of H2 will be
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Are these reactions correct?
I was told to do them in "reaction de deplacement simple", or simple moving reaction, I think. 1. Mg
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No question.
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Consider the reaction
Mg +2HCl ------>MgCl2 + H2 What is the minimum amount of 1.85M HCl is necessary to produce 28.5L of H2 at
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Well, well, well, it seems like we've got ourselves a stoichiometry problem here. Don't worry, I'll
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Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g) delta H1?
MgO(s) + 2HCl(aq) ->MgCl2(aq) + H2O(l) delta H2? To make these equations add up
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For the first equation I did 0 + 2(-167.159) -> 0 + 0 0 - 334.318 = deltaH1 = -334.318 Second
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