four resistor of resistances 1ohm,2ohm,3ohm,5ohm, are connected in series and afterwards in parallel.calculate the combined resistance in each case
this is one of the most basic setups. Clearly you need to do some reading.
series: R = 1+2+3+5 = 11
parallel:
1/R = 1/1 + 1/2 + 1/3 + 1/4
R = 12/25
hydrogen
how to get 4 get
To calculate the combined resistance when resistors are connected in series, you need to add up the individual resistances. When resistors are connected in parallel, you need to use the formula for calculating the equivalent resistance, which is the reciprocal of the sum of the reciprocals of individual resistances.
First, let's calculate the combined resistance when the resistors are connected in series:
1. Series Connection:
When resistors are connected in series, their resistances simply add up.
Total combined resistance (Rs) = R1 + R2 + R3 + R4
Rs = 1Ω + 2Ω + 3Ω + 5Ω
Rs = 11Ω
So, when the resistors are connected in series, the combined resistance is 11Ω.
Now let's calculate the combined resistance when the resistors are connected in parallel:
2. Parallel Connection:
When resistors are connected in parallel, you use the following formula to calculate the equivalent resistance (Rp):
1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4
Substituting the values:
1/Rp = 1/1Ω + 1/2Ω + 1/3Ω + 1/5Ω
To simplify, you can find the lowest common denominator (LCD) for the fractions, which is 30Ω:
1/Rp = 30/30 + 15/30 + 10/30 + 6/30
1/Rp = 61/30
Now, take the reciprocal of both sides:
Rp = 30/61Ω
So, when the resistors are connected in parallel, the combined resistance is approximately 0.49Ω (rounded to two decimal places).
To summarize:
- When the resistors are connected in series, the combined resistance is 11Ω.
- When the resistors are connected in parallel, the combined resistance is approximately 0.49Ω.
How did u get
12..and also 25?