a man
goes 10m towards north,then 20m towards east then displacement is what
noooooooooo
NOOOOOOOOO
35 m
59.57846734+99.86756321
what is
sqrt(10^2+20^2) in the direction of arctan 20/10 E of N
23
22m 60degree East of North
According to the question ,displacement is= root over of 10 metre square + 20 metre square =10 root 5 metre
is the displacement
To find the displacement, we need to determine the overall change in position.
In this case, the man first moves 10 meters towards the north, which means he is 10 meters above his starting position. Next, he moves 20 meters towards the east, which means he is 20 meters to the right of his previous position.
To find the displacement, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (displacement) is equal to the sum of the squares of the other two sides.
In this case, the displacement is the hypotenuse of the right triangle, with the northward movement as the vertical side (10 meters) and the eastward movement as the horizontal side (20 meters).
So, we can calculate the displacement as follows using the Pythagorean theorem:
displacement = √(vertical side^2 + horizontal side^2)
= √(10^2 + 20^2)
= √(100 + 400)
= √500
≈ 22.36 meters
Therefore, the displacement of the man is approximately 22.36 meters.