ow many grams of NH3 can be produced from 2.89mol of N2 and excess H2.
Express your answer numerically in grams.
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To determine the number of grams of NH3 produced from 2.89 mol of N2, we need to use the balanced chemical equation for the reaction between N2 and H2 to produce NH3.
The balanced chemical equation for the reaction is:
N2 + 3H2 → 2NH3
From the equation, we can see that one mole of N2 reacts with three moles of H2 to produce two moles of NH3.
To find the number of moles of NH3 produced, we can use the mole ratio between N2 and NH3:
2.89 mol N2 × (2 mol NH3 / 1 mol N2) = 5.78 mol NH3
Now, to convert the moles of NH3 to grams, we need to use the molar mass of NH3. The molar mass of NH3 is 17.03 g/mol.
5.78 mol NH3 × 17.03 g/mol = 98.40 g NH3
Therefore, 2.89 mol of N2 will produce 98.40 grams of NH3.