describe the end behavior of the graph of the polynomial function. Then evaluate the ntion for x=-4, -3, -2, -1, 0, 1, 2, 3, 4.

I'm confused on this. Help.

It might help if you provided the function. . .

Sorry about that.

So the function is :

y=x^4-2x^2-x-1

http://www.mathportal.org/calculators/polynomials-solvers/polynomial-graphing-calculator.php

To describe the end behavior of a polynomial function, we need to determine what happens to the graph as x approaches positive and negative infinity.

Here's how you can determine the end behavior:

1. Identify the degree of the polynomial function. The degree is the highest exponent of the variable in the function.

2. If the degree is even, the end behavior will match. If the leading coefficient (the coefficient of the term with the highest exponent) is positive, the graph will rise on both ends as x approaches positive and negative infinity. If it's negative, the graph will fall on both ends.

3. If the degree is odd, the end behavior will be opposite. If the leading coefficient is positive, the graph will rise on the right end as x approaches positive infinity and fall on the left end as x approaches negative infinity. If the leading coefficient is negative, it will be the opposite.

For example, if you have a polynomial function of degree 3 with a positive leading coefficient, the graph will rise on the right end and fall on the left end as x approaches positive and negative infinity, respectively.

Now, let's evaluate the function for the given values:
- Substitute each value of x into the polynomial function and calculate the result.
- For example, if the polynomial function is f(x) = 2x^3 + 3x^2 - x + 1:
- For x = -4, substitute it into f(x): f(-4) = 2(-4)^3 + 3(-4)^2 - (-4) + 1
- Calculate the result.

Repeat this process for each value of x.

I hope this helps clarify how to describe the end behavior of a polynomial function and how to evaluate the function for specific values of x.