When a driver presses the brake pedal, his car stops with an acceleration of -8.7 m/s2. How far will the car travel while coming to a complete stop if its initial speed was 10 m/s?

bals juice

To find the distance traveled by the car while coming to a complete stop, we can use the kinematic equation:

v^2 = u^2 + 2as

Where:
v = final velocity (0 m/s, as the car comes to a complete stop)
u = initial velocity (10 m/s)
a = acceleration (-8.7 m/s^2)
s = distance traveled

Rearranging the equation to solve for s:

s = (v^2 - u^2) / (2a)

Plugging in the given values:

s = (0^2 - 10^2) / (2 * -8.7)
s = (-100) / (-17.4)
s = 5.75 meters

Therefore, the car will travel a distance of 5.75 meters while coming to a complete stop.

To find the distance the car will travel while coming to a complete stop, we can use the equations of motion. In this case, we'll use the equation:

v^2 = u^2 + 2as

where:
- v is the final velocity (which is 0 m/s since the car is coming to a complete stop)
- u is the initial velocity (10 m/s)
- a is the acceleration (-8.7 m/s^2)
- s is the distance traveled while decelerating

Substituting the known values into the equation:

0^2 = (10 m/s)^2 + 2(-8.7 m/s^2)(s)

Simplifying:

0 = 100 m^2/s^2 - 17.4 m/s^2(s)

Rearranging the equation to solve for s:

17.4 m/s^2(s) = 100 m^2/s^2

s = 100 m^2/s^2 / 17.4 m/s^2

s = 5.75 m

Therefore, the car will travel approximately 5.75 meters while coming to a complete stop.

It takes the car 10/8.7 = 1.149 seconds to stop

s = 10t - 4.35t^2
so plug in t = 1.149 to find the distance