At stp what volume of SO2 gas will be produced when 2.00g of CS2 is burnt?
how many moles of CS2 is 2g?
how many moles of So2 are produced by one mole of CS2?
Then, since 1 mole fills 22.4L of volume at STP, you can figure the volume.
Or, check the related questions below
You will make two moles of SO2 for each mole of CS2 reacted.
Moles of CS2: 2.00/molmassCS2
moles of SO2: twice the above
STP volume of SO2: 22.4 x moles SO2
To find the volume of SO2 gas produced when 2.00g of CS2 is burnt at STP (Standard Temperature and Pressure), we need to follow a few steps:
1. Write the balanced chemical equation for the combustion of CS2:
CS2 + 3O2 -> CO2 + 2SO2
2. Calculate the number of moles of CS2 using its molar mass:
Molar mass of CS2 = 12.01 g/mol (C) + 32.07 g/mol (S) x 2 = 76.14 g/mol
Moles of CS2 = Mass of CS2 / Molar mass of CS2
= 2.00 g / 76.14 g/mol
3. Use the balanced equation to determine the mole ratio between CS2 and SO2:
From the balanced equation, 1 mole of CS2 reacts to produce 2 moles of SO2.
4. Calculate the moles of SO2 produced using the mole ratio:
Moles of SO2 = Moles of CS2 x (2 moles of SO2 / 1 mole of CS2)
5. Apply the ideal gas law to calculate the volume of SO2 gas at STP:
V = nRT / P
where V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)),
T is the temperature in Kelvin, and P is the pressure.
At STP, the temperature is 273.15 K and the pressure is 1 atm.
Plug in the values and calculate the volume of SO2 gas:
V = Moles of SO2 x R x T / P
By following these steps, you can find the volume of SO2 gas produced when 2.00g of CS2 is burnt at STP.