How much heat would be absorbed by 55 grams of copper when heated from 24 degrees Celsius to 40 degrees Celsius? The specific heat of copper is .385
My answer is 338.8 Joules. Is this correct?
Heat absorbed = mass * change in T * specific heat
I got the same answer.
55*16*.385=338.8J
To calculate the amount of heat absorbed by a substance, we can use the equation:
q = m * c * ΔT
where:
q is the heat absorbed (in Joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
Given:
m = 55 grams
c = 0.385 J/g°C
ΔT = (40°C - 24°C) = 16°C
Let's substitute the given values into the equation:
q = 55 g * 0.385 J/g°C * 16°C
q = 336.8 Joules
Therefore, the correct answer is 336.8 Joules, not 338.8 Joules.
To calculate the amount of heat absorbed by a substance, you can use the formula:
q = m * c * ΔT
Where:
q is the amount of heat absorbed (in Joules),
m is the mass of the substance (in grams),
c is the specific heat of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
Plugging in the values given in the problem:
m = 55 grams (given)
c = 0.385 J/g°C (given)
ΔT = 40°C - 24°C = 16°C
Now, we can calculate the amount of heat absorbed:
q = 55 g * 0.385 J/g°C * 16°C
q = 337.12 Joules
Therefore, the correct answer is approximately 337.12 Joules, which is very close to your response of 338.8 Joules. The slight difference may be due to rounding errors during calculations.