Chen is covering a 12-in. by 10-in. board with 1-inch-square tiles. He uses gray tiles to make six 2-in. by 2-in. squares. He covers the rest of the board with white tiles.
How many more white tiles than gray tiles will Chen use?
Six small rectangles inside a larger rectangle. Two adjacent sides of the larger rectangle are labeled twelve inches and ten inches. The six smaller rectangles appear to be the same size and are all shaded. Two adjacent sides of one of the smaller rectangles are labeled two inches and two inches.
120 tiles in all
6 * 2*2 = 24 gray
so, 96 white
96-24 = ? more white than gray
You don't have to be smart. Im only 10
the answer is 72 duh
To find out how many more white tiles than gray tiles Chen will use, we need to first calculate the total number of gray and white tiles used.
The area of the entire board is given by multiplying the length and width, which are 12 inches and 10 inches respectively: 12 inches * 10 inches = 120 square inches.
Next, we need to find the area covered by the six gray tiles. Each gray tile is 2 inches by 2 inches, so the area covered by each tile is 2 inches * 2 inches = 4 square inches. Since there are six gray tiles, the total area covered by the gray tiles is 4 square inches * 6 = 24 square inches.
Now, we can find the area covered by the white tiles. We subtract the area covered by the gray tiles from the total area of the board: 120 square inches - 24 square inches = 96 square inches.
Lastly, we need to convert the area covered by white tiles into the number of white tiles used. Since each white tile is 1 square inch, the number of white tiles used is simply equal to the area covered by white tiles. Therefore, Chen will use 96 white tiles.
To find the difference between the number of white and gray tiles, we subtract the number of gray tiles from the number of white tiles: 96 white tiles - 6 gray tiles = 90 more white tiles than gray tiles.