, a ball is thrown vertically upward from the top of the tower at 4.9 metres per second it strikes the pond near the base of the towers after 3 seconds the height of the tower is. Pls reply...
To find the height of the tower, we need to use the equation of motion for an object falling freely under gravity. The equation is:
h = u*t + (1/2)*g*t^2
Where:
h is the height of the tower
u is the initial velocity of the ball (4.9 m/s, upwards in this case)
t is the time taken by the ball to strike the pond (3 seconds)
g is the acceleration due to gravity (approximately 9.8 m/s^2)
Let's substitute the given values into the equation and solve for h:
h = (4.9 m/s) * (3 s) + (1/2) * (9.8 m/s^2) * (3 s)^2
h = 14.7 m + (1/2) * 9.8 m/s^2 * 9 s^2
h = 14.7 m + 44.1 m
h = 58.8 m
Therefore, the height of the tower is approximately 58.8 meters.
h(t) = x + 4.9t - 4.9t^2
if h=0 when t=3, then
x + 4.9(3) - 4.9(9) = 0
x = 29.4