Two urns both contain green balls and red balls. Urn 1 contains 6 green balls and 4 red balls and urn 2 contains 8 green balls and 7 red balls. A ball is drawn from each urn.What is the probability that both balls are red
11/25
A.2/75
B.7/50
C.7/25
D.14/15
D.14/75
Sry about that
4/10 * 7/15 = 14/75
To find the probability that both balls drawn are red, we need to calculate the probability of drawing a red ball from each urn and then multiply them together.
Urn 1 contains 6 green balls and 4 red balls. The total number of balls in urn 1 is 6 + 4 = 10.
The probability of drawing a red ball from urn 1 is 4/10.
Urn 2 contains 8 green balls and 7 red balls. The total number of balls in urn 2 is 8 + 7 = 15.
The probability of drawing a red ball from urn 2 is 7/15.
To calculate the probability of both events happening, we multiply the probabilities together:
Probability of drawing a red ball from urn 1 * Probability of drawing a red ball from urn 2
= (4/10) * (7/15)
= 28/150
= 14/75
So, the probability that both balls drawn are red is 14/75.