A 2.0ìF capacitor, a 13ìF capacitor, and a 20ìF capacitor are connected in parallel. What is their equivalent capacitance? Could you explain how to do?
A skier of mass 44.4 kg comes down a slope
of constant angle 26 ◦ with the horizontal.
What force normal to the slope is exerted by
the skis (neglect friction)? The acceleration
of gravity is 9.8 m/s
2
.
Answer in units of N
If two capacitors are in parallel, they hold more charge for a given voltage.
We know that
C = Q/V
here
C1 = Q1/V
C2 = C2/V
C1 + C2 = (Q1+Q2)/V
so
final C = C1 + C2
In other words, if in parallel, add capacitances because you add charges per unit voltage
any acceleration is down the slope, perpendicular to the force we are interested in.
That normal force is the component of weight normal to the hill surface
which is
m g cos 25
To find the equivalent capacitance of capacitors connected in parallel, you can simply add up the individual capacitance values. In this case, the capacitors have capacitance values of 2.0ìF, 13ìF, and 20ìF.
To calculate the equivalent capacitance, add the capacitance values together:
2.0ìF + 13ìF + 20ìF = 35ìF
Therefore, the equivalent capacitance of the three capacitors connected in parallel is 35ìF.