A man applies a force of 150N to pull a 20kg box with a rope that makes an angle of 60percent with the horizontal.The box experience a kinetic friction of 15N. Calculate the acceleration of the box.
ch +h2o
To calculate the acceleration of the box, we need to determine the net force acting on it. The net force is the vector sum of all the forces acting on the box.
In this case, the forces acting on the box are the applied force (150 N), the force due to friction (-15 N), and the force of gravity.
1. Force due to friction: The force of kinetic friction is given as 15 N. Since the box is in motion, we can assume there is kinetic friction opposing its motion.
2. Force of gravity: The force of gravity can be calculated using the equation F = m * g, where m is the mass of the box (20 kg) and g is the acceleration due to gravity (approximately 9.8 m/s^2). Therefore, the force of gravity is F = 20 kg * 9.8 m/s^2 = 196 N.
3. Applied force: The applied force is given as 150 N.
Now, let's calculate the net force:
Net force = Applied force + Force due to friction + Force of gravity
= 150 N + (-15 N) + 196 N
= 331 N
Since we know that force = mass * acceleration (F = m * a), we can rearrange the equation to find the acceleration:
Acceleration = Net force / mass
= 331 N / 20 kg
= 16.55 m/s^2
Therefore, the acceleration of the box is approximately 16.55 m/s^2.