The bumper car ride at the state fair has 3 red cars, 4 green cars, and 2 blue cars. Joe is first in line for the ride and is assigned a car at random. Bill in next in line and is randomly assigned a car. What is the probability that both joe and bill will drive a red bumper car? Express your answer as a percent. If necessary, round your answer to the nearest tenth.
8.3
9 cars, 3 of which are red
so prob(red,red) = (3/9)(2/8)
= 1/12
you do the decimal stuff
To find the probability that both Joe and Bill will drive a red bumper car, we need to calculate the probability of Joe getting a red car and the probability of Bill getting a red car.
The total number of cars is 3 red + 4 green + 2 blue = 9 cars.
The probability of Joe getting a red car is 3 red cars / 9 cars = 1/3.
After Joe gets a red car, there are 8 cars left, with 2 of them being red.
The probability of Bill getting a red car is 2 red cars / 8 cars = 1/4.
To find the joint probability (both events happening), we multiply these probabilities.
Probability of both Joe and Bill getting a red car = (1/3) * (1/4) = 1/12.
To express this as a percent, we multiply by 100.
Probability as a percent = (1/12) * 100 = 8.3%.
Therefore, the probability that both Joe and Bill will drive a red bumper car is approximately 8.3%.
To find the probability that both Joe and Bill will drive a red bumper car, we need to determine the probability of Joe getting a red car and the probability of Bill getting a red car, and then multiply those probabilities together.
First, let's calculate Joe's probability of getting a red car. There are a total of 9 cars (3 red + 4 green + 2 blue). Since Joe is assigned a car at random, the probability of him getting a red car is 3 out of 9, or 3/9.
Next, let's calculate Bill's probability of getting a red car. After Joe has chosen a car, there are now 8 cars left. The number of red cars remains the same at 3 since it wasn't specified whether the selected car is replaced or not. Therefore, the probability of Bill getting a red car is 3 out of 8, or 3/8.
Now, to find the probability that both Joe and Bill will drive a red bumper car, we multiply their individual probabilities:
P(Joe getting a red car) times P(Bill getting a red car) = (3/9) * (3/8)
Simplifying, (3/9) * (3/8) = 9/72 = 1/8.
The probability that both Joe and Bill will drive a red bumper car is 1 out of 8.
Expressed as a percent, 1/8 * 100 = 12.5%.
So, the probability that both Joe and Bill will drive a red bumper car is approximately 12.5%.