A sealed cylinder of gas contains nitrogen gas at 1.00 ✕ 103 kPa pressure and a temperature of 28°C. The cylinder is left in the sun, and the temperature of the gas increases to 50.°C. What is the new pressure in the cylinder?

8.75

P1V1/T1=P2V2/T2

P2=T2/T1*P1V1/V2 and v1=v2 so

P2=(273+50)/(273+28) * 1E3kPa

To find the new pressure of the gas inside the cylinder, we can use the ideal gas law equation:

PV = nRT

Where:
P is the pressure of the gas (in Pascal or Pa)
V is the volume of the gas (in cubic meters or m^3)
n is the number of moles of the gas
R is the ideal gas constant (8.314 J/(mol·K))
T is the temperature of the gas (in Kelvin or K)

First, we need to convert the initial and final temperatures from Celsius to Kelvin:

Initial temperature (T1) = 28°C = 28 + 273 = 301 K
Final temperature (T2) = 50°C = 50 + 273 = 323 K

Now, we can rearrange the ideal gas law equation to solve for the new pressure (P2):

P1V1 / T1 = nR (1)
P2V2 / T2 = nR (2)

Since the volume (V1 = V2) and the number of moles (n) can be assumed to be constant for this problem, we can cancel them out in equations (1) and (2), giving:

P1 / T1 = P2 / T2

To find P2, we can plug in the known values:

P1 = 1.00 x 10^3 kPa
T1 = 301 K
T2 = 323 K

Now we can solve for P2:

P2 = (P1 x T2) / T1
= (1.00 x 10^3 kPa x 323 K) / 301 K
≈ 1074.415 kPa

Therefore, the new pressure in the cylinder is approximately 1074.415 kPa.

To find the new pressure in the cylinder, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure
V = volume
n = number of moles of gas
R = ideal gas constant
T = temperature in Kelvin

First, let's convert the temperatures to Kelvin by adding 273.15 to them.
Initial temperature (Ti) = 28°C + 273.15 = 301.15 K
Final temperature (Tf) = 50°C + 273.15 = 323.15 K

The number of moles (n) remains constant, so the ratio of initial and final pressures is equal to the ratio of initial and final temperatures:
(Pi / Pf) = (Ti / Tf)

Substituting the values we have:
(1.00 × 10³ kPa / Pf) = (301.15 K / 323.15 K)

Now we can solve for Pf:
Pf = (1.00 × 10³ kPa) × (323.15 K / 301.15 K)

Calculating this gives:
Pf = 1.08 × 10³ kPa

Therefore, the new pressure in the cylinder is approximately 1.08 × 10³ kPa.