What is the solution to the following equation?
3x(x-4)+5=12
3 x^2 - 12 x - 7 = 0
x = [12 +/- sqrt (144 + 84 ) } / 6
[ 12 +/- sqrt(228) ] /6
[ 12 +/- 2 sqrt(57) ]/6
2 +/- (1/3)sqrt(57)
3x(x-4)+5=12
x = [12 +/- sqrt (144 + 84 ) } / 6
[ 12 +/- sqrt(228) ] /6
[ 12 +/- 2 sqrt(57) ]/6
2 +/- (1/3)sqrt(57)