if x= 3+2^2, find the value of (^x - 1/x)^2
if x= 3+2^2, find the value of (^x-1/x)^2
what is ^x ? square root? If so, we have
(√x - 1/x)^2
= x - 2/√x + 1/x^2
3+2^2 = 3+4 = 7, so we have
7 - 2/√7 + 1/49
That's kind of strange, so maybe you can clarify the notation and the grouping. Some parentheses would be helpful in that regard.
if x=1-^2, find the value of (x-1/x)^3
simplify: 1/1+^2 + 1/^2+^3 + 1/^3+^4
To find the value of (^x - 1/x)^2, we first need to find the value of x.
Given that x = 3 + 2^2, we can simplify this expression:
x = 3 + 2^2
x = 3 + 4
x = 7
Now that we know the value of x, we can substitute it into the expression (^x - 1/x)^2:
(^x - 1/x)^2 = (^(7) - 1/7)^2
Calculating the value of ^x, which represents raising a number to the power of x, we have:
^(7) = 7^7 (seven raised to the power of seven)
To find the value of 7^7, you can use a calculator or a programming language that supports large numbers. It will give you the result:
7^7 = 823543
Now substituting this value back into the expression (^x - 1/x)^2, we have:
(^x - 1/x)^2 = (823543 - 1/7)^2
We can now calculate 1/7:
1/7 = 0.142857143
Substituting this back into the expression:
(^x - 1/x)^2 = (823543 - 0.142857143)^2
Now we can calculate the difference and square it:
(^x - 1/x)^2 = (823542.857143)^2
Calculating (823542.857143)^2, we get the final answer:
(^x - 1/x)^2 = 678223072426.530612244897959183673469