If the volume of a balloon is 5.0 L at 22 degrees Celsius, what will be the new volume if the balloon is heated to 75 degrees Celsius? Should the volume increase or decrease?
5/22=x/75
x=17.045
Correct.
To determine the new volume of the balloon when heated to 75 degrees Celsius, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, assuming the pressure and amount of gas remain constant.
To use Charles's Law, we need to convert the temperatures from degrees Celsius to Kelvin. The Kelvin temperature scale starts at absolute zero, which is -273.15 degrees Celsius. To convert Celsius to Kelvin, simply add 273.15 to the Celsius temperature.
Given that the initial volume is 5.0 L at 22 degrees Celsius, we convert this to Kelvin:
Initial Kelvin temperature = 22 + 273.15 = 295.15 K
We also have the final temperature, which is 75 degrees Celsius:
Final Kelvin temperature = 75 + 273.15 = 348.15 K
Now we can use the formula for Charles's Law:
(Volume initial / Temperature initial) = (Volume final / Temperature final)
Plugging in the values:
(5.0 L / 295.15 K) = (Volume final / 348.15 K)
To find the new volume, we can cross-multiply:
Volume final = (5.0 L x 348.15 K) / 295.15 K
Calculating this equation will give us the new volume of the balloon when heated to 75 degrees Celsius.
After performing the calculation, the new volume is approximately 5.92 L. Therefore, the volume of the balloon will increase as the temperature increases from 22 degrees Celsius to 75 degrees Celsius.