There are 120 tickets being sold for a raffle contest. There is one winning ticket. Lana buys 10 tickets. What are the probability she will win the prize
probability of 1/12; one out of twelve chance
0.0833
To find the probability of Lana winning the prize, we need to know the total number of tickets sold and the number of tickets Lana bought.
Given:
Total number of tickets = 120
Number of tickets Lana bought = 10
The probability of Lana winning can be calculated by dividing the number of favorable outcomes (winning ticket) by the number of possible outcomes (total number of tickets).
Number of favorable outcomes = 1 (winning ticket)
Number of possible outcomes = 120 (total number of tickets)
Probability = Number of favorable outcomes / Number of possible outcomes
= 1 / 120
Therefore, the probability of Lana winning the prize is 1/120.
To calculate the probability of Lana winning the prize, we need to determine the ratio of the number of favorable outcomes to the total number of possible outcomes.
In this case, there is one winning ticket out of a total of 120 tickets being sold. Lana buys 10 tickets, so we can consider these 10 tickets as one favorable outcome. The total number of possible outcomes is still 120.
Therefore, the probability of Lana winning the prize can be calculated as:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 10 / 120
Probability = 1/12
So, the probability of Lana winning the prize is 1/12, which can be written as approximately 0.08333 or 8.33%.