From the equation below, how many grams of barium sulfate can be produced from 20.8 g of barium chloride?
BaCl2 + Na2SO4 -> BaSO4 + 2NaCl
mols BaCl2 = grams/molar mass = ?
Use the coefficients in the balancd equation to convert mols BaCl2 t mols BaSO4.
Then convert mols BaSO4 to grams. g BaSO4 = mols BaSO4 x molar mass BaSO4.
To determine the amount of barium sulfate that can be produced, we need to use the concept of stoichiometry and balance the equation.
The balanced equation is:
BaCl2 + Na2SO4 -> BaSO4 + 2NaCl
According to the equation, 1 mole of barium chloride (BaCl2) reacts with 1 mole of sodium sulfate (Na2SO4) to produce 1 mole of barium sulfate (BaSO4) and 2 moles of sodium chloride (NaCl).
First, we need to convert the given mass of barium chloride (BaCl2) to moles using its molar mass. The molar mass of barium chloride (BaCl2) is 137.33 g/mol (137.33 = molar mass of Ba + 2 * molar mass of Cl).
20.8 g of BaCl2 * (1 mol / 137.33 g) = 0.1513 mol of BaCl2
Using the stoichiometric ratios from the balanced equation, we can determine the number of moles of barium sulfate (BaSO4) that can be produced from the given amount of BaCl2.
From the balanced equation, the ratio of BaCl2 to BaSO4 is 1:1. Therefore, 0.1513 mol of BaCl2 will produce an equal amount of BaSO4.
So, 0.1513 mol of BaSO4 can be produced.
Finally, we can convert the moles of barium sulfate into grams using its molar mass. The molar mass of barium sulfate (BaSO4) is 233.39 g/mol.
0.1513 mol of BaSO4 * (233.39 g/mol) = 35.31 g of BaSO4
Therefore, approximately 35.31 grams of barium sulfate can be produced from 20.8 grams of barium chloride.
To determine the grams of barium sulfate that can be produced from 20.8 g of barium chloride, we need to use the concept of stoichiometry and the given balanced chemical equation.
Let's start by finding the molar mass of BaCl2 and BaSO4:
- Molar mass of BaCl2 = 137.33 g/mol (barium chloride)
- Molar mass of BaSO4 = 233.39 g/mol (barium sulfate)
Next, we need to convert the given mass of barium chloride (20.8 g) into moles:
- Moles of BaCl2 = given mass / molar mass
= 20.8 g / 137.33 g/mol
≈ 0.1514 mol
Now, let's use the coefficients in the balanced chemical equation to determine the moles of barium sulfate produced:
- From the balanced equation:
BaCl2 + Na2SO4 → BaSO4 + 2NaCl
We can see that for every 1 mol of BaCl2, 1 mol of BaSO4 is produced. Thus, the moles of BaSO4 can be determined as:
- Moles of BaSO4 = Moles of BaCl2
= 0.1514 mol
Finally, we can convert moles of BaSO4 back into grams by multiplying by the molar mass of BaSO4:
- Mass of BaSO4 = Moles of BaSO4 × molar mass
= 0.1514 mol × 233.39 g/mol
≈ 35.34 g
Therefore, approximately 35.34 grams of barium sulfate can be produced from 20.8 grams of barium chloride.