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The sum of the first 15 terms of an arithmetic series is 1290. The sum of the first 16 terms is 1464. Find t16. Find S20
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The sum of the first 15 terms of an arithmetic series is 1290. The sum of the first 16 terms is 1464.
Find t16? Find S20
Top answer:
clearly T16 = 1464-1290 = 174 16/2 (a+174) = 1464 a = 9 T16 = 9+15d = 174 d=11 S20 = 20/2
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The sum of the first 15 terms of an arithmetic series is 1290. The sum of the first 16 terms is 1464. Find t16. Find S20
Top answer:
sum(15) = (15/2)(2a + 14d) = 1290 2a + 14d =172 sum(16) = (16/2)(2a + 15d) = 1464 2a + 15d = 183
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The sum of the first 15 terms of an arithmetic series is 1290. The sum of the first 16 terms is 1464.
Find t16? Find S20
Top answer:
clearly T16 = 1464-1290 = 174 S16 = 16/2 (a+174) = 1464 a = 9 T16 = 9+15d = 174 d=11 S20 = 20/2
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1)The sum of 6 terms of an arithmetic series is 45, the sum of 12 terms is -8. Find the first term and the common difference?
2)I
Top answer:
You have to know the formula for the sum of n terms of an AS Sum(6) = 3(2a + 5d) 6a + 15d = 45 ---
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the sum of the first n terms of an arithmetic series is -51. the series has a constant difference of -1.5 and a first term of
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To find the number of terms in the sum: 1. Start with the series' first term, which is given as 4.
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The sum of the first 5 terms of an arithmetic series is 70. The sum of the first 10 terms of this arithmetic series is 210. What
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The answer is 42/5
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The sum of the first 9 terms of an arithmetic series is 144, and the sum of the first 14 terms is 329. Find the first 4 terms of
Top answer:
Fhhh
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The sum of the 1st nine terms of an arithmetic series is 216. The 1st,3rd and the 7th terms of series form the 1st three terms
Top answer:
just write what they told you: 9/2 (2a+8d) = 216 (a+2d)/(a) = (a+6d)/(a+2d) Now solve for a and d.
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show your work The 6th term of an arithmetic series is 13, the sum of the first 40 terms is 3420. Find
the sum of the first 30
Top answer:
Sum of first 30 terms = (30/2)[2a + (30 - 1)d] a = 6th term = 13 d = common difference = (3420 -
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The sum of the first 20 terms of an arithmetic series is identical to the sum of the first 22 terms. If the common difference is
Top answer:
sum of 20 = 10(2a + 19d) = 10(2a - 38) = 20a - 380 sum of 22 = 11(2a + 21d) = 11(2a - 42) 22a - 462
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