calculate the volume of gas at STP that is produced when 1g of silver nitrate is heated. the unbalanced reaction is: AgNO3(s)=Ag(s)+NO2(g)+O2(g)
I can't balance equation but mols are n=m/M =1/168=5,95multiply10^-3mol. so help with other please
Balance the equation. Then
mols AgNO3 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols AgNO3 to mols NO2 and do the same to convert to mols O2.
Add mols NO2 + mols O2
Convert total mols of the gas to volume in liters by L gas = mols gas x (22.4L/mol) = ? L.
If you have trouble, first go back and look at the problem I did a day or so ago. If you still have trouble post your work and explain in detail what you don't understand.
This is similar to the problem I worked for you two days ago with the 100 g iron producing rust.
http://www.jiskha.com/display.cgi?id=1431803547
equation:2AgNO3=Ag2+2NO2+O2
The volume of the gas produced is 0.04L/mok
To calculate the volume of gas at STP (standard temperature and pressure) produced when 1g of silver nitrate is heated, we need to follow these steps:
1. Convert the mass of silver nitrate (AgNO3) to the number of moles. To do this, we need to know the molar mass of silver nitrate.
The molar mass of AgNO3 = 107.87 g/mol (atomic mass of Ag = 107.87 g/mol, atomic mass of N = 14.01 g/mol, atomic mass of O = 16.00 g/mol)
Number of moles of AgNO3 = 1g / 107.87 g/mol = 0.00926 mol (rounded to five decimal places)
2. Use the balanced chemical equation to determine the mole ratio between AgNO3 and the gas produced, which is NO2 in this case.
The balanced equation is: 2AgNO3(s) = 2Ag(s) + 2NO2(g) + O2(g)
As per the equation, 2 moles of AgNO3 produce 2 moles of NO2.
3. Calculate the number of moles of NO2 produced.
Number of moles of NO2 = 0.00926 mol / 2 = 0.00463 mol (rounded to five decimal places)
4. Finally, we can use the ideal gas law at STP, where the volume can be calculated using the equation:
V = n * Vm
V = volume of gas at STP (Unknown)
n = number of moles of NO2
Vm = molar volume of gas at STP
The molar volume of gas at STP is approximately 22.4 L/mol.
V = 0.00463 mol * 22.4 L/mol = 0.1038 L
Therefore, when 1g of silver nitrate is heated, approximately 0.1038 liters of NO2 gas will be produced at STP.