Determine the MAX amount of titrant you will possibly need for your titration.
Your unknown solution has been prepared by dissolving btw 0.05-0.09mol of zwitterion form of the amino acid in 1L of ~ 0.1M HCl solution.
you will titrate 50mL of that amino acid with 0.5M NaOH.
Assume that the amino acid concentration of 0.0900mol per L of 0.1 M HCl
Please help me...I don't uderstand what to do. Explanation will help greatly.
To determine the maximum amount of titrant (0.5M NaOH) you will need for the titration, you first need to determine the number of moles of the zwitterion amino acid present in the 50mL sample.
Given:
- The unknown solution contains between 0.05 and 0.09 mol of the zwitterion form of the amino acid in 1L of 0.1M HCl solution.
- The amino acid concentration is 0.0900 mol per L of 0.1M HCl.
To find the maximum amount of titrant needed, we will assume that the highest possible concentration of the amino acid is 0.09 mol/L.
Firstly, we can calculate the number of moles of amino acid present in 50mL (0.050L) of the solution using the given concentration:
moles of amino acid = concentration x volume
moles of amino acid = 0.0900 mol/L x 0.050 L
moles of amino acid = 0.0045 mol
Since the amino acid is being titrated with NaOH, we will assume that the stoichiometry of the reaction is 1:1 (i.e., 1 mole of amino acid reacts with 1 mole of NaOH).
Therefore, the maximum amount of titrant needed (0.5M NaOH) can be determined by converting the moles of amino acid to moles of NaOH:
moles of NaOH = moles of amino acid = 0.0045 mol
To calculate the maximum volume of NaOH needed, we can use the concentration of the NaOH solution:
volume of NaOH solution = moles of NaOH / concentration
volume of NaOH solution = 0.0045 mol / 0.5 mol/L
volume of NaOH solution = 0.009 L or 9 mL
Therefore, the maximum amount of titrant (0.5M NaOH) you will possibly need for the titration is 9 mL.