In mixing a weed killing chemical a 40% solution of the chemical is mixed with an 85% solution to get 20 L of a 60% solution. How much of each solution is needed?

If x at 40%, the rest (20-x) is 85%. So,

.40x + .85(20-x) = .60(20)

amount of 40% stuff --- x L

amount of 85% stuff --- 20-x L

.4x + .85(20-x) = .60x

go with Steve, I messed up, right side is .60(20)

Well, it seems like you're dealing with some mixed-up vegetation. But don't worry, I'll help you weed out the problem! Let's break it down:

Let's call the amount of the 40% solution you need to mix "x" liters. And since the total volume of the final solution is 20L, the amount of the 85% solution will be 20 - x liters.

Now, let's talk about the percentages. The desired solution is 60% concentration. That means, from our x liters of the 40% solution, we'll have 0.4x liters of pure weed killer. And from our (20 - x) liters of the 85% solution, we'll have 0.85(20 - x) liters of pure weed killer.

Adding these two amounts together should give us the desired concentration. So, let's set up the equation:

0.4x + 0.85(20 - x) = 0.6(20)

Now, let the math game begin!

To solve this problem, we will use the method of mixing solutions.

Let's first assign variables to the two unknown quantities in the problem. Let's say x represents the amount (in liters) of the 40% solution needed and y represents the amount (in liters) of the 85% solution needed.

Now, let's set up the equations based on the given information:

Equation 1: x + y = 20 (since we want a total volume of 20 liters)

Equation 2: (0.40x + 0.85y) / 20 = 0.60 (since we want a 60% solution)

Simplifying Equation 2:

0.40x + 0.85y = 0.60 * 20
0.40x + 0.85y = 12

Now we have a system of equations:

Equation 1: x + y = 20
Equation 2: 0.40x + 0.85y = 12

To solve this system, we can use the method of substitution or elimination. Let's solve it using the substitution method.

1. Solve Equation 1 for x:
x = 20 - y

2. Substitute x in Equation 2 with the value found from Equation 1:
0.40(20 - y) + 0.85y = 12
8 - 0.40y + 0.85y = 12
0.45y = 4
y = 4 / 0.45
y = 8.89 liters

3. Substitute the value of y back into Equation 1 to find x:
x = 20 - 8.89
x = 11.11 liters

So, to obtain a 20 L of a 60% solution, you would need 11.11 liters of the 40% solution and 8.89 liters of the 85% solution.