Nitric acid can be produced by the reaction of gaseous nitrogen dioxide with water.
3NO2(g) + H2O(§¤) −>
2HNO3(§¤) + NO(g)
If 794 L of NO2 gas react with water, what volume of NO gas will be produced? Assume the gases are measured under the same conditions.
Answer in units of L.
When working with gases one may use volume as if L were mols.
794L NO2 x (1 mol NO/3 mol NO2) = ?
OK but you are not allowed that many significant figures.
I agree
Well, according to the balanced equation, for every 3 moles of NO2 gas reacting with water, we get 1 mole of NO gas as a product.
However, we don't know the initial number of moles of NO2 gas. All we know is the volume of NO2 gas, which is 794 L.
So, in order to find the volume of NO gas, we need to convert the volume of NO2 gas into moles, and then use the mole ratio to find the volume of NO gas.
To convert the volume of NO2 gas into moles, we need to use the ideal gas law (PV = nRT) and know the temperature, pressure, and number of moles of NO2 gas. Since this information is missing from the question, I can't provide an answer in units of L.
But hey, if you need some laughter therapy, I'm here for you!
To find the volume of NO gas produced, we can use the stoichiometry of the balanced equation. The coefficients in the balanced equation represent the ratio of moles, which can be used to calculate the volume.
Given:
Number of moles of NO2 = volume of NO2 (in liters)
From the balanced equation:
3 moles of NO2 react to produce 1 mole of NO gas
So, we need to convert the volume of NO2 (in liters) to moles using the ideal gas law equation:
PV = nRT
Where:
P is the pressure (assumed constant)
V is the volume of gas (in liters)
n is the number of moles of gas
R is the ideal gas constant (0.0821 L·atm/(mol·K))
T is the temperature in Kelvin (assumed constant)
Since the gases are measured under the same conditions, we can assume that the pressure, temperature, and R are constant. Therefore, we can directly relate the volume of NO2 to the moles of NO2.
Now, let's calculate the moles of NO2:
Moles of NO2 = Volume of NO2 (in liters) / Volume of 1 mole of gas
We also know from the balanced equation that 3 moles of NO2 produce 1 mole of NO gas. Therefore, we can set up the following ratio:
3 moles of NO2 / 1 mole of NO = Moles of NO2 / Moles of NO
Using the ratio of moles of NO2 to moles of NO, we can calculate the moles of NO by multiplying the moles of NO2 by the ratio.
Now, let's calculate the moles of NO:
Moles of NO = Moles of NO2 × (1 mole of NO / 3 moles of NO2)
Finally, to convert the moles of NO to volume, we use the same ideal gas law equation mentioned earlier:
Volume of NO = Moles of NO × Volume of 1 mole of gas
Converting the volume of NO to liters, we get the result.
Note: Make sure to convert the given temperature to Kelvin before using it in the calculations.