the sides of a rectangle are given in centimeters up length 4x+3 down length x+ 6y,left width 3x+1 right width 4x-y. find x and y and area of the rectangle .solution 4x+3=x+6y . y=3x+3÷6 also 4x-y=3x+1.x=y+1
I know this was given yearssss ago, but thanks!!!!! It helped a lot today
Yes that's right. You have to equate the expressions for widths and for the lengths, since left and right widths (and lengths) have the same dimensions.
You may rewrite the equation for y=3x+3÷6 as
y = (3x + 3)/6
And now you have an expression for y, we can substitute it to the other equation you got:
x = y + 1
x = (3x + 3)/6 + 1
And solve for x. After you got the value of x, you can solve for y.
Amazing
y=3x+3÷6 as y=(3x+3)/6
substitute the equation
x=y+1
x=(3x+3)/6 +1
least i can try
I got it by doing 4(3)+3=15
3+6(2)=15
=150cm
I think you are confusing the solution for the values of x and y with the solution for the area of the rectangle.
Let's go back to the equations you derived:
- Length: 4x + 3 = x + 6y
- Width: 3x + 1 = 4x - y
From the first equation, we can solve for x in terms of y:
4x + 3 = x + 6y
3x = 6y - 3
x = 2y - 1
Substituting this expression for x into the second equation:
3(2y-1) + 1 = 4(2y-1) - y
6y - 2 + 1 = 8y - 4 - y
y = 3
So, we have found that y = 3. Now we can substitute this value back into either one of the equations to find the corresponding value of x:
4x + 3 = x + 6y
4x + 3 = x + 6(3)
4x + 3 = x + 18
3x = 15
x = 5
Therefore, we have found that x = 5 and y = 3.
Now, we can calculate the area of the rectangle:
Area = (4x + 3)(3x + 1)
Area = (4(5) + 3)(3(5) + 1)
Area = (23)(16)
Area = 368 cm^2
I hope this clarifies the solution for you!
I don't understand
4x-y=x+6y
4x+3=x+6y
X=3,Y=2
I see. Can you please show me how you got these values for x and y? It will be easier for me to help you understand.
Area=L × w=4x+3=x+6y
y=4x_3+3+6
y=3+3+6
y=6+6
y=12.
L×w=4x_y =3x+1
X=4x_3x+1+1
1x=2
x=2