what is the volume occupied by 2 moles of ammonia at s.t.p(1mole of gas at s.t.p=22.4)
1 orange costs $1.00; what's the cost of 2 oranges?
1 mol occupies 22.4 L; what's the volume occupied by 2 mols?
To calculate the volume occupied by 2 moles of ammonia at STP (Standard Temperature and Pressure), we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (STP = 1 atm)
V = volume
n = moles of gas (2 moles)
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature in Kelvin (STP = 273.15 K)
Rearranging the equation to solve for volume (V):
V = nRT / P
Substituting the given values:
V = (2 moles) × (0.0821 L·atm/mol·K) × (273.15 K) / (1 atm)
Calculating the result:
V = 44.8 L
Therefore, 2 moles of ammonia occupies a volume of 44.8 liters at STP.
To find the volume occupied by 2 moles of ammonia at standard temperature and pressure (STP), we can use the relationship between moles and volume at STP.
According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain an equal number of molecules. At STP, one mole of any gas occupies a volume of 22.4 liters.
To find the volume occupied by 2 moles of ammonia at STP, we can use the following calculation:
Volume of 1 mole of gas at STP = 22.4 liters
Volume of 2 moles of gas at STP = 2 × 22.4 = 44.8 liters
Therefore, the volume occupied by 2 moles of ammonia at STP is 44.8 liters.