Battery acid is 4.27MH2SO4(AQ.) And density of 1.25g/ml . What is the molality of H2SO4 in the solution
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To find the molality of H2SO4 in the solution, we need to first understand what molality is. Molality (m) is a concentration unit that represents the number of moles of solute (in this case, H2SO4) per kilogram of solvent (in this case, water).
To calculate molality, we need to determine the number of moles of H2SO4 and the mass of the solvent.
Given:
- Battery acid concentration: 4.27 M (this represents the molarity of H2SO4)
- Density of battery acid: 1.25 g/ml
First, let's convert the density of battery acid to kilograms per liter (kg/L) since molality requires the mass of solvent in kilograms.
1. Convert the density from grams per milliliter (g/ml) to kilograms per liter (kg/L):
Density = 1.25 g/ml
1 L = 1000 ml
Density = 1.25 g/ml * (1 kg / 1000 g) * (1000 ml / 1 L) = 1.25 kg/L
Now we have the density of the solution in kg/L. Next, we need to calculate the number of moles of H2SO4.
2. Calculate the number of moles of H2SO4:
Molarity (M) = 4.27 M (given)
Volume (V) = 1 L (since we are assuming 1L of solution)
Molarity (M) = Moles of solute (H2SO4) / Volume of solution (V)
4.27 M = Moles of H2SO4 / 1 L
Therefore, Moles of H2SO4 = 4.27
Now we have the number of moles of H2SO4. Finally, we can calculate the molality of H2SO4.
3. Calculate the molality (m):
Molality (m) = Moles of solute (H2SO4) / Mass of solvent (in kilograms)
The mass of solvent can be calculated by multiplying the volume of the solution (in liters) by its density (in kg/L):
Mass of solvent = Volume of solution * Density
Mass of solvent = 1 L * 1.25 kg/L = 1.25 kg
Molality (m) = 4.27 moles / 1.25 kg
Molality (m) = 3.416 mol/kg (rounded to three decimal places)
Therefore, the molality of H2SO4 in the solution is approximately 3.416 mol/kg.
Study
What does AQ mean?
Why is it not 4.27 M?