Write the balanced net ionic equation for the following reaction and determine the conjugate acid-base pairs.

HNO3(aq)+Li2CO3(aq)<--->LiNo3(aq)+LiHCO3(aq)
Which component in the net ionic equation is the acid, the base, the conjugate base, and the conjugate acid
Thank you
This formula was given to us I came up with H+(aq)+CO3(2-)(aq)<-->HCO3(-)(aq) and the net ionic acid HNO3(aq), the net ionic base as CO3(-)(aq),and the conjugate base as NO3(-)(aq), and the conjugate acid as HCO3(-)(aq)

This looks ok to me; I assume you've seen my earlier response.

To write the balanced net ionic equation for the given reaction, we first need to write the complete ionic equation.

The given chemical equation is: HNO3(aq) + Li2CO3(aq) ↔ LiNO3(aq) + LiHCO3(aq)

First, let's write the complete ionic equation by breaking down the aqueous compounds into their ions:

H+(aq) + NO3-(aq) + 2Li+(aq) + CO3(2-)(aq) ↔ Li+(aq) + NO3-(aq) + Li+(aq) + HCO3-(aq)

Now, we can cancel out the common ions on both sides of the equation to obtain the net ionic equation:

H+(aq) + CO3(2-)(aq) ↔ HCO3-(aq)

In the net ionic equation, the H+ (hydronium ion) is the acid, and the CO3(2-) (carbonate ion) is the base.

Conjugate acid-base pairs are formed when an acid donates a proton (H+) and forms its conjugate base, which is the acid after losing a proton. Similarly, a base accepts a proton and forms its conjugate acid.

Therefore, in the net ionic equation:
- H+ is the acid
- HCO3- is the base
- HCO3- is the conjugate acid (derived from the base)
- CO3(2-) is the conjugate base (derived from the acid)

Thus, the conjugate acid-base pairs in this reaction are H+/HCO3- and HCO3-/CO3(2-).

To find the balanced net ionic equation and determine the acid-base pairs, let's break down the given chemical equation and identify the species involved:

HNO3(aq) + Li2CO3(aq) ↔ LiNO3(aq) + LiHCO3(aq)

First, let's write the complete ionic equation by separating the soluble compounds into their respective ions:

H+(aq) + NO3-(aq) + 2 Li+(aq) + CO3^(2-)(aq) ↔ Li+(aq) + NO3-(aq) + Li+(aq) + HCO3^-(aq)

Next, we can cancel out the spectator ions (ions that appear on both sides of the equation):

H+(aq) + CO3^(2-)(aq) ↔ HCO3^-(aq)

Now, let's identify the acid, base, conjugate acid, and conjugate base:

- Acid: HNO3(aq) → H+(aq) (The species that donates a proton/hydrogen ion)
- Base: Li2CO3(aq) → CO3^(2-)(aq) (The species that accepts a proton/hydrogen ion)
- Conjugate acid: HCO3^-(aq) (The species formed when the base accepts a proton)
- Conjugate base: NO3^-(aq) (The species formed when the acid donates a proton)

The balanced net ionic equation is H+(aq) + CO3^(2-)(aq) ↔ HCO3^-(aq), and the acid-base pairs are:
- Acid: HNO3(aq)
- Base: Li2CO3(aq)
- Conjugate acid: HCO3^-(aq)
- Conjugate base: NO3^-(aq)