A net charge of 73 mC passes through the cross-sectional area of a wire in 9 s .
What is the current in the wire? The fun- damental charge is 1.602 × 10−19 C.
1A is 1C/s
You have
73mC/9s = 8.11mA
the net charge is not relevant here, since all we need is the number of Coulombs.
To find the current in the wire, we need to use the formula for electric current:
Current (I) = Charge (Q) / Time (T)
We are given the charge, Q, which is 73 mC (milliCoulombs), and the time, T, which is 9 s.
However, the charge is given in milliCoulombs and we need to convert it to Coulombs to match the units of the fundamental charge.
1 milliCoulomb (mC) = 10^-3 Coulombs (C)
So, 73 mC is equal to 73 × 10^-3 C.
Now, we can calculate the current using the formula:
I = Q / T
I = (73 × 10^-3 C) / 9 s
I = 8.1111 × 10^-3 C/s
However, the fundamental charge is given as 1.602 × 10^-19 C. To find the current in terms of fundamental charges, we can divide the calculated current by the fundamental charge:
I = (8.1111 × 10^-3 C/s) / (1.602 × 10^-19 C)
I = 5.067 × 10^16 fundamental charges/s
Therefore, the current in the wire is approximately 5.067 × 10^16 fundamental charges per second.