Leslie and Jess were racing at school. Leslie was able to complete the race in 12 1/2 seconds, whereas jess finished in13 1/10 seconds. How much faster did Leslie run?
PLs help me!!
the difference between two numbers is found by subtraction:
13 1/10 - 12 1/2
= 12 11/10 - 12 5/10
= 6/10 or 3/5
Thank u v. Much!!!
To find out how much faster Leslie ran compared to Jess, we need to find the difference in their times.
First, let's convert both times to a common denominator.
Leslie's time is given as 12 1/2 seconds. To convert the mixed number to an improper fraction, we multiply the whole number (12) by the denominator (2) and add the numerator (1):
12 * 2 + 1 = 24 + 1 = 25
So Leslie's time can be written as 25/2 seconds.
Jess's time is given as 13 1/10 seconds. Converting it to an improper fraction, we multiply the whole number (13) by the denominator (10) and add the numerator (1):
13 * 10 + 1 = 130 + 1 = 131
So Jess's time can be written as 131/10 seconds.
Now, let's find the difference between Leslie's and Jess's times:
25/2 - 131/10 = 125/20 - 131/10
To subtract the fractions, we need a common denominator. The least common multiple (LCM) of 20 and 10 is 20.
So we need to convert both fractions to have a denominator of 20:
(125/20) * (10/10) = 1250/200
(131/10) * (2/2) = 262/20
Now we can subtract the fractions:
1250/200 - 262/20 = (1250 - 262) / 20
= 988/20
Simplifying the fraction, we get:
988/20 = 494/10 = 49 4/10
Therefore, Leslie ran 49 4/10 seconds faster than Jess.