A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds?
Given: g on moon = –1.63 meters/second
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To determine how far the feather will have fallen on the moon's surface in 9.00 seconds, we can use the formula for distance fallen due to gravity:
distance = 0.5 * g * t^2
where:
g is the acceleration due to gravity (-1.63 m/s^2)
t is the time (9.00 seconds)
Substituting the given values:
distance = 0.5 * (-1.63 m/s^2) * (9.00 s)^2
First, square the value of 9.00 s:
distance = 0.5 * (-1.63 m/s^2) * (81.00 s^2)
Next, multiply 81.00 s^2 by -1.63 m/s^2:
distance = -0.5 * (131.43 m)
Finally, multiply -0.5 by 131.43 m to get the final result:
distance ≈ -65.72 m
Therefore, the feather will have fallen approximately 65.72 meters on the moon's surface in 9.00 seconds.