A 20 C charge experiences a 2 N force in an electric field. What is the strength of the electric field?
To find the strength of the electric field, we need to use Coulomb's Law. Coulomb's Law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
In this case, we are given the force experienced by a 20 C charge, so we can write the equation as:
F = (k * q1 * q2) / r^2
Where:
F is the force experienced by the charge,
k is Coulomb's constant (9 x 10^9 N*m^2/C^2),
q1 and q2 are the magnitudes of the charges,
and r is the distance between the charges.
In our case, the force (F) is given as 2 N, and the charge (q1) that experiences the force is 20 C. We want to find the electric field strength (E), which is the force per unit charge.
So we rearrange the equation to solve for E:
E = F / q1
Plugging in the given values:
E = 2 N / 20 C
E = 0.1 N/C
Therefore, the strength of the electric field is 0.1 N/C.