Calculate the energy in Joules, of a photon of blue light have a frequency of 5.0 x 10^14 hertz.

E=hv
v=C/ƛ
v= 3.00x10^8/5.0x10^14= 6x10^-7

E=(6.626x10^-34) (6x10^-7)= 3.9x10^40 Joules

What am I doing wrong? I got this wrong on my exam and have a final tomorrow, so any help would be appreciated. Thanks, Stacie

You have assigned the values wrong. v is nu (which I don't know how to make) and that is frequency. You already have frequency so that v = C/lambda is not only not needed but is incorrect. So you substitute directly into E = hv = 6.626E-34*5E14 = 3.3E-19 J.

It seems like you made a small mistake while calculating the frequency of the light. Let's go through the steps again to find the correct answer.

First, let's start with the formula you correctly mentioned: E = hv, where E is the energy of the photon, h is the Planck's constant, and v is the frequency of the light.

Next, we need to calculate the frequency of the light using the formula v = c/λ, where v is the frequency, c is the speed of light, and λ is the wavelength of the light.

In this case, you have the frequency of the light given (5.0 x 10^14 Hz), so we can use this directly.

v = 5.0 x 10^14 Hz

Now, we need to calculate the energy by substituting the frequency into the formula E = hv.

E = (6.626 x 10^-34 J·s) x (5.0 x 10^14 Hz)

Calculating this, we get:

E = 3.313 x 10^-19 J

So the correct answer is 3.313 x 10^-19 Joules, not 3.9 x 10^40 Joules.

I hope this helps! Good luck on your final exam!