How many kilojoules of heat are released when 185 g of benzene freezes at its freezing/melting point? (Heat of fusion for benzene = 127 J/g, Heat of vaporization for benzene = 393 J/g)
q = mass x heat fusion = ?
mass x heat fusion= 23,495
The problem asks for kJ; convert your answer in Joules to kJ.
To find the amount of heat released when benzene freezes, we need to calculate the heat of fusion.
Given:
Mass of benzene (m) = 185 g
Heat of fusion (ΔHf) = 127 J/g
To find the total heat released (Q), we can use the formula:
Q = m * ΔHf
Substituting the given values:
Q = 185 g * 127 J/g
Now we can calculate:
Q = 23,495 J
Therefore, when 185 g of benzene freezes at its freezing/melting point, 23,495 J (or 23.495 kJ) of heat is released.