Natalie bought 2 bags and 3 times as many pouches. She spent a total of $368. Each bah cost $24 more than a pouch. How much did 1 pouch cost?
Cost=2*(24+P)+3*2*P
368=48 +2P + 6P
8P=368-48=320
P=40 dollars for each pouch. Goodneess, Natalie needs to shop at KMart.
thank you
To find the cost of one pouch, we can solve this problem step by step.
Let's assume the cost of one pouch is "x" dollars.
Since Natalie bought 2 bags and 3 times as many pouches, the number of pouches she bought would be 3 * 2 = 6 pouches.
Now, the total cost of the pouches is 6 * x = 6x dollars.
We are also given that each bag cost $24 more than a pouch, so the cost of one bag would be x + $24.
Since Natalie bought 2 bags, the total cost of the bags is 2 * (x + $24) = 2x + $48 dollars.
The total amount she spent is the sum of the cost of bags and pouches, which is $368.
Therefore, we can write the equation as 6x + 2x + $48 = $368.
Combining like terms, we have 8x + $48 = $368.
Now, let's isolate the variable by subtracting $48 from both sides: 8x = $368 - $48 = $320.
To find the value of x, we need to divide both sides of the equation by 8: x = $320 / 8 = $40.
Hence, the cost of one pouch is $40.