A net charge of 73 mC passes through the
cross-sectional area of a wire in 9 s.
What is the current in the wire? The fundamental
charge is 1.602 × 10−19 C.
i = Q/t or
amps = coulombs/second
you do not need the electron charge for this - red herring intended to confuse you.
To find the current in the wire, we need to use the formula:
Current (I) = charge (Q) / time (t)
In this case, the charge that passes through the wire is given as 73 mC (milliCoulombs), and the time taken is given as 9 s.
However, we need to convert the charge from milliCoulombs to Coulombs in order to match the unit of the fundamental charge, which is given as 1.602 × 10^(-19) C.
To convert from milliCoulombs to Coulombs, we need to divide the charge by 1000 (since 1 milliCoulomb = 1/1000 Coulomb):
73 mC / 1000 = 0.073 C
Now that we have the charge in Coulombs, we can calculate the current:
I = 0.073 C / 9 s ≈ 0.0081 A
Therefore, the current in the wire is approximately 0.0081 Amps.