eliminate parameters of x=1+cos t
y=1-sin t
graph the parametric equations
x = 1 + cos t
y = 1 - sin t
cos t = (x-1)
sin t = (1-y)
cos^2 t = (x-1)^2
sin^2 t = (1-y)^2
----------------- add
1 = (x-1)^2 + (1-y)^2
your turn :)
why squared?
because I learned in a trig course the sin^2 x + cos^2 x = 1
what is the graph for this equation?
how to graph equation?
hey, just pick some points
note
x^2+y^2 = r^2 = circle
i didn't get a circle by using 0, pi/6, pi/4, pi/3, and pi/2?
how do you eliminate the parameters for x=1-t^2 and y=1+t?
t^2 = 1-x
t = y-1 so t^2 = y^2-2y+1
so
y^2-2y+1 = 1 - x