1) Solve the equation for p. Identify any extraneous solutions. √p=-1
A) -1 is a solution of the original equation. 1 is an extraneous solution.
B) 1 is a solution of the original equation.
C) 1 is a solution of the original equation. -1 is an extraneous solution.
D) There is no real solution.
If this helps, the p is only covered by the square root sign, and the = sign and -1 is not covered. Thank you so much for any help, since I am confused about this problem.
Is the answer D?
Good answer. By definition, √p is positive.
In fact 1 is an extraneous solution.
To solve the equation √p = -1 and identify any extraneous solutions, we need to isolate p and then check if the obtained solution is valid.
Step 1: Square both sides of the equation:
(√p)^2 = (-1)^2
p = 1
Step 2: Substitute the obtained value of p (p = 1) back into the original equation to check for extraneous solutions:
√(1) = -1
Since the square root of a number is always non-negative, there are no real solutions for p in this equation. Therefore, the correct answer is:
D) There is no real solution.