Calculate the hydronium ion concentration of blood which has a pH of 7.24.
7.17 x 10-4 M
5.75 x 10-8 M
1.15 x 10-7 M
0.86 M
none of the above
I had chose 1.15*10^-7 by doing the log equation -log(1.15...) and I but it goether with -log(10*^-7.24) and it was closest to 14 and that's how I thought you were supposed to do this question. But, when I put 5,75*10^-8 in that equation it gives me 7.24. Is that the answer?
Yes, 5.75E-8 is the answer for pH = 7.24.
You should do pH = -log(H3O^+), then
7.24 = -log(H3O^+)
-7.24 = log(H3O^+)
(H3O^+) = 10^-7.24 = 5.75E-8
Well, let's see if I can help clarify things for you. The pH of a solution is calculated by taking the negative logarithm of the hydronium ion concentration. In this case, since we know the pH is 7.24, we need to find the corresponding hydronium ion concentration.
If you take the negative logarithm of 1.15 x 10^-7, you get a pH value of 6.94, which is lower than the given pH of 7.24. So that can't be the answer.
But if you take the negative logarithm of 5.75 x 10^-8, you get a pH value of 7.24! So, based on these calculations, it appears that the correct answer is 5.75 x 10^-8 M.
Remember, pH is a measure of acidity, so a lower pH means a higher concentration of hydronium ions. And in this case, the hydronium ion concentration of blood with a pH of 7.24 is approximately 5.75 x 10^-8 M.
Hope that helps!
To calculate the hydronium ion concentration (H3O+) given the pH of a solution, you can use the formula:
[H3O+] = 10^(-pH)
For the given pH of 7.24, let's plug it into the formula:
[H3O+] = 10^(-7.24)
Calculating this, we get:
[H3O+] = 5.75 x 10^(-8) M
So the correct answer is 5.75 x 10^(-8) M, which means option 2 is correct. Therefore, the answer is not 1.15 x 10^(-7) M.
Please note that the pH scale is logarithmic, so the concentration of H3O+ ions decreases significantly as the pH value increases.
To calculate the hydronium ion concentration (H3O+) from the pH of a solution, you can use the equation:
pH = -log[H3O+]
In this case, you know that the pH of blood is 7.24. So, you can set up the equation as:
7.24 = -log[H3O+]
To solve for [H3O+], you need to take the antilog (reversing the log function) of both sides of the equation. In this case, the antilog is calculated as 10 raised to the power of the equation. So, you have:
[H3O+] = 10^(-7.24)
Using a calculator, you find that [H3O+] ≈ 5.75 x 10^(-8) M.
Therefore, based on your calculation, the correct option is 5.75 x 10^(-8) M.