I need someone to please help show me how to simplify radicals.
27 -2/3
____
27 -1/3
Where are the radicals here? I do not see them? I know it's hard to type them, but could you please specify, maybe with parenthesis?
That is how it is shown in my math book
There aren't any radicals in this problem then. This problem alone though is a pain itself. Firstly, since both fractions are negative on each side, you can eliminate them and reorder so you have (2/3+27 / 1/3+27)
Then, I would suggest multiplying both sides of the fraction by the denominator's conjugate.
This should net you a fraction divided by a fraction, and you can reorder them by using the reciprocal of the denominator fraction, which allows you to now multiply the two fractions.
Do you need me to explain with the numbers, or do you think you got it?
I think I still need a little more help. I want to make sure that I fully understand this, so I won't have any issues with the other problems
Look on the new post you made. I placed a step by step process
To simplify radicals, we need to simplify the numerator and the denominator separately. Let's start with the numerator:
1. Start by finding the prime factors of 27:
27 = 3 × 3 × 3
2. Next, simplify the expression -2/3:
-2/3 = -2 × (1/3) = -2/3
3. Rewrite the numerator as a product of the prime factors and the simplified fraction:
27 - 2/3 = (3 × 3 × 3) - (2/3)
Now let's simplify the denominator:
1. Find the prime factors of 27:
27 = 3 × 3 × 3
2. Rewrite the denominator as a product of the prime factors:
27 - 1/3 = (3 × 3 × 3) - (1/3)
Now that we have simplified the numerator and the denominator separately, we can rewrite the expression:
(3 × 3 × 3) - (2/3)
____________
(3 × 3 × 3) - (1/3)
To proceed further, we need to apply the rules of arithmetic to simplify this expression. However, it seems like some information is missing in the original question. Are there any numbers or variables given after the fractions?