Kenji, a pet store employee, wants to fit two fish tanks on one table. One fish tank is 4 feet wide and the other fish tank is 2/5 of a foot wide. When placed next to each other, what is the total width of the two fish tanks?

Simplify your answer and write it as a proper fraction or as a whole or mixed number.

2 2/5

To find the total width of the two fish tanks when placed next to each other, we need to add the widths of the two fish tanks.

First, we need to convert both widths to the same units. We can convert 4 feet to inches, which is a more convenient unit for addition. Since 1 foot is equal to 12 inches, the first fish tank's width is 4 feet * 12 inches/foot = 48 inches.

Now, let's convert the width of the second fish tank, which is 2/5 of a foot. To convert it to inches, we multiply by 12 since 1 foot is equal to 12 inches. So, the width of the second fish tank is (2/5) * 12 inches = 4.8 inches.

Finally, adding the two widths together: 48 inches + 4.8 inches = 52.8 inches.

Since the question asks for the answer as a proper fraction or as a whole or mixed number, we need to convert the decimal to a fraction or mixed number. The decimal 52.8 can be written as the mixed number 52 and 8/10. Simplifying the fraction by dividing both the numerator and denominator by their greatest common factor, which is 2, we get 52 and 4/5.

Therefore, the total width of the two fish tanks when placed next to each other is 52 and 4/5 inches.

4 + 2/5 = 4 2/5