Calculate the weight in grams of potassium hydrogen phthalate (KHP, KHC2H3O2, MW 202.2 g/mole) required to neutralize 25.00 ml of 0.1 M NaOH solution.

KHP + NaOH ==> NaKP + H2O

mols NaOH = M x L = ?
mols KHP = mols NaOH since the equation tells you 1 mol KHP = 1 mol NaOH
Then mols = grams/molar mass. You know molar mass and mols, solve for grams.

To calculate the weight of potassium hydrogen phthalate (KHP) required to neutralize 25.00 ml of 0.1 M NaOH solution, we need to use the balanced chemical equation between KHP and NaOH.

The balanced chemical equation is:

KHP + NaOH -> Water + KNaC8H4O4

From the balanced equation, we can see that 1 mole of KHP reacts with 1 mole of NaOH to form 1 mole of KNaC8H4O4.

Given that we have 25.00 ml of 0.1 M NaOH solution, we need to convert it to moles.

First, let's calculate the number of moles of NaOH:

25.00 ml * 0.1 mol/L = 2.50 mmol

Since the molar ratio between KHP and NaOH is 1:1, the number of moles of KHP required will also be 2.50 mmol.

Now, let's convert the moles of KHP to grams using its molar mass:

2.50 mmol * 202.2 g/mol = 505.5 mg

Finally, we can convert the mass to grams:

505.5 mg = 0.5055 g

Therefore, the weight of KHP required to neutralize 25.00 ml of 0.1 M NaOH solution is approximately 0.5055 grams.

To calculate the weight of potassium hydrogen phthalate required to neutralize 25.00 ml of 0.1 M NaOH solution, you need to follow these steps:

1. Determine the moles of NaOH: The given volume of 0.1 M NaOH solution is 25.00 ml. To calculate the moles, you need to multiply the volume (in liters) by the molarity, using the formula:
Moles = Volume (liters) × Molarity
Since the volume is given in milliliters, you need to convert it to liters by dividing it by 1000:
Moles = 25.00 ml ÷ 1000 ml/L = 0.025 L
Moles = 0.025 L × 0.1 M = 0.0025 moles

2. Write the balanced chemical equation: The balanced equation representing the neutralization reaction between NaOH and KHC2H3O2 is:
NaOH + KHC2H3O2 → NaKC2H3O2 + H2O

3. Use stoichiometry to find the moles of KHC2H3O2: From the balanced equation, you can see that the mole ratio between NaOH and KHC2H3O2 is 1:1. Therefore, the moles of KHC2H3O2 will be the same as the moles of NaOH.

4. Calculate the weight of KHC2H3O2: The molecular weight of KHC2H3O2 is given as 202.2 g/mole. To find the weight of KHC2H3O2 in grams, you can multiply the moles of KHC2H3O2 by its molecular weight:
Weight (grams) = Moles × Molecular weight
Weight = 0.0025 moles × 202.2 g/mole = 0.5055 grams

Therefore, the weight in grams of potassium hydrogen phthalate (KHP) required to neutralize 25.00 ml of 0.1 M NaOH solution is approximately 0.5055 grams.