If 74.5% of exhaled air is nitrogen, what is the partial pressure of nitrogen in exhaled air. Assume that the total pressure of exhaled air is 760 mmhg.
XN2 = 0.745
pN2 = XN2*Ptotal
pN2 = 0.745*1 atm = 0.746 atm or
0.745*760 = ? mm = pN2
To find the partial pressure of nitrogen in exhaled air, we need to calculate the partial pressure using the given percentage and the total pressure.
1. Convert the given percentage of nitrogen to a decimal: 74.5% = 0.745
2. Calculate the partial pressure of nitrogen by multiplying the decimal value by the total pressure:
Partial pressure of nitrogen = 0.745 * 760 mmHg
3. Simplify the expression:
Partial pressure of nitrogen = 565.4 mmHg
Therefore, the partial pressure of nitrogen in exhaled air is 565.4 mmHg.
To calculate the partial pressure of nitrogen in exhaled air, we can use the concept of partial pressure. Partial pressure is the pressure exerted by an individual gas within a mixture of gases.
First, we need to find the partial pressure of nitrogen, given that it constitutes 74.5% of exhaled air.
Step 1: Convert the percentage to a decimal.
74.5% = 0.745
Step 2: Calculate the partial pressure of nitrogen by multiplying the decimal value by the total pressure of exhaled air.
Partial pressure of nitrogen = 0.745 * 760 mmHg
Calculating this expression, we have:
Partial pressure of nitrogen = 0.745 * 760 mmHg
Simplifying the equation, we find:
Partial pressure of nitrogen = 565.4 mmHg
Therefore, the partial pressure of nitrogen in exhaled air is 565.4 mmHg.