The voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has been reduced three times. Write the voltage in exponential form.___________________________________
What was the original voltage in the circuit?________________________________
you guys make no sense. neither does brainly or gauthmath. no help on any of the sites
original: v
1st reduction: v^2
2nd: v^4
3rd: v^8
so, v^8 = 27/125
v = (3/5)^(3/8)
To write the voltage in exponential form, we need to find the expression that represents the voltage being multiplied by itself each time it is reduced.
Since the voltage is reduced three times, we can use the exponent of 3. The voltage is given as 27/125 of a volt, so we can rewrite it as (27/125)^3.
Therefore, the voltage in exponential form is (27/125)^3.
To find the original voltage in the circuit, we need to take the cube root of the given voltage.
By taking the cube root of (27/125)^3, we can simplify it as follows:
Cube root of (27/125)^3 = 27/125.
Therefore, the original voltage in the circuit is 27/125 of a volt.