How do i find the 12th term of the sequence

36,18,9....

using a formula

http://www.jiskha.com/display.cgi?id=1428961174

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To find the 12th term of the sequence 36, 18, 9... using a formula, we can first observe that each term is being divided by 2 to get the next term.

We can express this pattern in the form of a formula:

Tn = T1 * (r)^(n-1)

Where:
Tn = the nth term of the sequence
T1 = the first term of the sequence
r = common ratio
n = the term number

For this sequence, the first term (T1) is 36 and the common ratio (r) is 1/2 (since each term is divided by 2).

Plugging these values into the formula, we have:

T12 = 36 * (1/2)^(12-1)

T12 = 36 * (1/2)^11

T12 = 36 * (1/2048)

T12 = 36/2048

T12 = 0.017578125

Therefore, the 12th term of the sequence is approximately 0.0176.

To find the 12th term of the given sequence using a formula, we need to determine the pattern or the rule that governs the sequence.

In this case, we can observe that each term is obtained by dividing the previous term by 2.

So, the sequence can be represented by the formula:

nth term = first term * common ratio^(n - 1)

Here, the first term is 36, and the common ratio is 1/2 (since each term is obtained by dividing the previous term by 2).

Using this formula, we can substitute the values to find the 12th term:

12th term = 36 * (1/2)^(12 - 1)

Simplifying the expression:

= 36 * (1/2)^11
= 36 * (1/2)^11
= 36 * (1/2048)
= 36/2048
= 0.01758 (rounded to 5 decimal places)

Therefore, the 12th term of the given sequence is approximately 0.01758.