How many grams of solid zinc metal will completely react with 100.0 mL of 0.0525 M HCl, if zinc chloride and hydrogen gas are the only products?
Zn + 2HCl ==> H2 + ZnCl2
mols HCl = M x L = ?
Using the coefficients in the balanced equation, convert mols HCl to mols Zn.
Now convert mols Zn to grams. g = mols Zn x atomic mass Zn.
0.172
1.72 g Zn
To find out how many grams of solid zinc metal will completely react with HCl, we need to use stoichiometry.
First, let's write the balanced equation for the reaction between zinc metal (Zn) and hydrochloric acid (HCl):
Zn + 2HCl --> ZnCl2 + H2
From the balanced equation, we can see that 1 mole of Zn reacts with 2 moles of HCl. We know the concentration of HCl (0.0525 M) and the volume of HCl (100.0 mL), so we can calculate the number of moles of HCl:
moles of HCl = concentration (M) x volume (L)
= 0.0525 M x 0.1000 L
= 0.00525 moles
According to the stoichiometry of the balanced equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, to react completely with 0.00525 moles of HCl, we need half the number of moles of Zn:
moles of Zn = 0.00525 moles / 2
= 0.002625 moles
Finally, we can calculate the mass of zinc (Zn) using its molar mass:
mass of Zn = moles of Zn x molar mass of Zn
The molar mass of zinc is 65.38 g/mol.
mass of Zn = 0.002625 moles x 65.38 g/mol
= 0.1718 grams
Therefore, 0.1718 grams of solid zinc metal will completely react with 100.0 mL of 0.0525 M HCl if zinc chloride and hydrogen gas are the only products.